4t^2-t-60=0

Solution for 4t^2-t-60=0 equation:

4t^2-t-60=0

We add all the numbers together, and all the variables

4t^2-1t-60=0

a = 4; b = -1; c = -60;
Δ = b2-4ac
Δ = -12-4·4·(-60)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-31}{2*4}=\frac{-30}{8}
=-3+3/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+31}{2*4}=\frac{32}{8}
=4
$